目录

83. Remove Duplicates from Sorted List

82. Remove Duplicates from Sorted List II

1836. Remove Duplicates From an Unsorted Linked List

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删除链表中的结点合集

83. Remove Duplicates from Sorted List

代码：

/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode() : val(0), next(nullptr) {}
 *     ListNode(int x) : val(x), next(nullptr) {}
 *     ListNode(int x, ListNode *next) : val(x), next(next) {}
 * };
 */
class Solution {
public:
    ListNode* deleteDuplicates(ListNode* head) {
        if(head == nullptr)
            return head;
        ListNode* pre = head;
        ListNode* cur = head->next;
        ListNode* nex = nullptr;
        while(cur){
            nex = cur->next;
            if(cur->val == pre->val){
                pre->next = nex;
                delete cur;
                cur = nex;
            }else{
                pre = cur;
                cur = nex;
            }
        }
        return head;
    }
};

82. Remove Duplicates from Sorted List II

 

代码：

/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode() : val(0), next(nullptr) {}
 *     ListNode(int x) : val(x), next(nullptr) {}
 *     ListNode(int x, ListNode *next) : val(x), next(next) {}
 * };
 */
class Solution {
public:
    ListNode* deleteDuplicates(ListNode* head) {
        if(head == nullptr)
            return head;
        ListNode* dummy = new ListNode(-1,head);
        ListNode* prepre = dummy;
        int pre_val = head->val;
        ListNode* pre = head;
        ListNode* cur = pre->next;
        ListNode* nex = nullptr;
        while(cur){
            nex = cur->next;
            if(cur->val == pre_val){
                prepre->next = nex;
                if(pre){
                    delete pre;
                    pre = nullptr;
                }
                delete cur;
                cur = nex;
            }else{
                if(pre){
                    prepre = pre;
                }
                pre = cur;
                pre_val = pre->val;
                cur = nex;
            }
        }
        ListNode* ans = dummy->next;
        delete dummy;
        return ans;
    }
};

1836. Remove Duplicates From an Unsorted Linked List

 

代码：

/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode() : val(0), next(nullptr) {}
 *     ListNode(int x) : val(x), next(nullptr) {}
 *     ListNode(int x, ListNode *next) : val(x), next(next) {}
 * };
 */
class Solution {
public:
    ListNode* deleteDuplicatesUnsorted(ListNode* head) {
        unordered_map<int,int> count;
        ListNode* cur = head;
        while(cur){
            count[cur->val]++;
            cur = cur->next;
        }
        ListNode* dummy = new ListNode(-1,head);
        ListNode* pre = dummy;
        cur = head;
        ListNode* post = nullptr;
        while(cur){
            post = cur->next;
            if(count[cur->val] > 1){
                pre->next = post;
                // delete cur;
                cur = post;
            }else{
                pre = cur;
                cur = post;
            }
        }

        ListNode* ans = dummy->next;
        delete dummy;
        return ans;
    }
};