2.整除末尾无空格用printf“ ”#includestdio.h int main(){ int count0; for(int i100;i1000;i){ if(i%50i%60){ printf(%d,i); count; if(count%100) printf(\n); else printf( ); } } return 0; }3.字符串内排序冒泡排序双重循环遍历字符交换逆序对实现升序字符串的升序降序本质上是ASCII码的比较就可以用排序对数字进行升序降序进而对字符升序降序#includestdio.h #includestring.h void bubble_sort(char s[], int len) { int i 0, j 0; char temp; for (i 0; i len - 1; i) { for (j 0; j len - 1 - i; j) { if (s[j] s[j 1]) { temp s[j]; s[j] s[j 1]; s[j 1] temp; } } } } int main() { char s[201]; while (scanf(%s, s) ! EOF) { int len strlen(s); bubble_sort(s, len); printf(%s\n, s); } return 0; }4.水仙花数#includestdio.h #includestring.h #includemath.h int main(){ int m0,n0; while(scanf(%d %d,m,n)!EOF){ if(m0n0) break; int flag1; for(int im;in;i){ int ai,b0,c0; while(a!0){ ba%10; cpow(b,3); a/10; } if(ci){ printf(%d ,i); flag0; } } if(flag1) printf(no); printf(\n); } return 0; }EZ题#includestdio.h #includestring.h #includemath.h int main(){ int n0; scanf(%d,n); if(n90) printf(A); else if(n90n80) printf(B); else if(n80n70) printf(C); else if(n70n60) printf(D); else printf(E); return 0; }#includestdio.h #includestring.h #includemath.h int main(){ int n0;//最好用long型下面scanf用ld scanf(%d,n); int b0;//bonus奖金 if(n100000) bn*0.1; else if(n200000) b100000*0.1(n-100000)*0.075; else if(n400000) b100000*0.1100000*0.075(n-200000)*0.05; else if(n600000) b100000*0.1100000*0.075200000*0.05(n-400000)*0.03; else if(n1000000) b100000*0.1100000*0.075200000*0.05200000*0.03(n-600000)*0.015; else b100000*0.1100000*0.075200000*0.05200000*0.03400000*0.015(n-1000000)*0.01; printf(%d,b); return 0; }5.计算Sn#includestdio.h #includestring.h #includemath.h int main(){ int a,n; scanf(%d %d,a,n); int sum0,b0; for(int i0;in;i){ bb*10a; sumb; } printf(%d,sum); return 0; }6.平方和与倒数和#includestdio.h int main(){ int a,b,c; scanf(%d %d %d,a,b,c); double sum0; for(int i1;ia;i){ sumi; } for(int i1;ib;i){ sumi*i; } for(int i1;ic;i){ sum1.0/i; } printf(%.2f,sum); return 0; }7.分数求和#includestdio.h #includestring.h #includemath.h float fib(int n){ if(n2) return 1.0; else return fib(n-1)fib(n-2); } int main(){ int N; scanf(%d,N); int i0; float sum0; for(i1;iN;i){ sumfib(i2)/fib(i1); } printf(%.2f,sum); return 0; }8.促销计算c#includeiostream using namespace std; int main(){ float n0; while(cinn){ if(n1000) coutdiscount1,paynendl; else if(n2000) coutdiscount0.95,payn*0.95endl; else if(n3000) coutdiscount0.9,payn*0.9endl; else if(n5000) coutdiscount0.85,payn*0.85endl; else coutdiscount0.8,payn*0.8endl; } return 0; }10.斐波那契数列非递归法重要***#includeiostream using namespace std; long long fib(int n){ long long res; if(n0) res1; else if(n1) res1; else if(n2) res2; else{ long long i3,a1,b1,c2; for(i3;in;i){ resabc; ab; bc; cres; } } return res; } int main(){ int n0; while(cinn){ coutfib(n)endl; } return 0; }11.%g#includebits/stdc.h using namespace std; int main(){ int a,b; cinab; double average; average(ab)/2.0; printf(%g,average); return 0; }提高1.字符串带空格逆序gets可以带空格读取一行#includestdio.h #includestring.h void reverse(char arr[],int n){ int l0,rn-1; char temp; while(lr){ temparr[l]; arr[l]arr[r]; arr[r]temp; l; r--; } } int main(){ char arr[100]; gets(arr); int n strlen(arr); reverse(arr,n); printf(%s,arr); return 0; }2.日期小难#includestdio.h int main(){ const char *day[7]{Thursday,Friday,Saturday,Sunday,Monday,Tuesday,Wednesday}; int mon[13]{0,31,29,31,30,31,30,31,31,30,31,30,31}; int m,n; scanf(%d,m); scanf(%d,n); int total0; int i0;//下标 for(int j4;jm;j){ totalmon[j]; } total-12; totaln; printf(%s,day[total%7]); return 0; }3.字符移动拼接#includestdio.h #includestring.h int main(){ char arr[100],a[100],b[100]; scanf(%s,arr); int i0,j0,k0; while(arr[i]!\0){ if(arr[i]0arr[i]9){ b[k]arr[i]; k; i; } else{ a[j]arr[i]; j; i; } } // ✅ 必须加这两句 a[j] \0; // 给 a 加结束符 b[k] \0; // 给 b 加结束符 strcat(a,b); printf(%s,a); return 0; }4.加密算法#includestdio.h #includestring.h int main(){ char arr[100]; gets(arr); int lenstrlen(arr); int i0; for(i0;ilen;i){ if(arr[i]aarr[i]x) arr[i]3; else if(arr[i]xarr[i]z) arr[i](arr[i]3-a)%26a; else if(arr[i]Aarr[i]X) arr[i]3; else if(arr[i]Xarr[i]Z) arr[i](arr[i]3-A)%26A; } printf(%s,arr); return 0; }核心公式背下来小写(c - a 3) % 26 a大写(c - A 3) % 26 A