122. 买卖股票的最佳时机 II - 力扣(LeetCode) 
 
 
 
class Solution {
    public int maxProfit(int[] prices) {
        if(prices.length == 0){
            return 0;
        }
        int min = prices[0];
        int result = 0;
        for(int i=1;i<prices.length;i++){
            if(prices[i] > min){
                result += (prices[i] - min);
                min = prices[i];
                continue;
            }
            if(min > prices[i]){
                min = prices[i];
            }
        }
        return result;
        // int buyIndex = -1;
        // int result = 0;
        // for (int i = 0; i < prices.length - 1; i++) {
        //     if (prices[i] <= prices[i + 1]) {
        //         if (buyIndex == -1) {
        //             buyIndex = i;
        //         }
        //         continue;
        //     }
        //     if (buyIndex != -1) {
        //         result += prices[i] - prices[buyIndex];
        //         buyIndex = -1;
        //     }
        // }
        // if (buyIndex != -1) {
        //     result += prices[prices.length - 1] - prices[buyIndex];
        // }
        // return result;
    }
} 
 55. 跳跃游戏 - 力扣(LeetCode)
class Solution {
    public boolean canJump(int[] nums) {
        if(nums.length <= 1){
            return true;
        }
        
        int[] canReachPos = new int[nums.length];
        for(int i=0;i<canReachPos.length;i++){
            canReachPos[i] = i + nums[i];
        }
        
        int canReachMaxRemotePos = canReachPos[0];
        for(int i=0;i<=canReachMaxRemotePos;i++){
            if(canReachPos[i] >= nums.length-1){
                return true;
            }
            
            if(canReachPos[i] > canReachMaxRemotePos){
                canReachMaxRemotePos = canReachPos[i];
            }
        }
        
        return false;
    }
} 
 45. 跳跃游戏 II - 力扣(LeetCode)
class Solution {
    public int jump(int[] nums) {
        if (nums.length <= 1) {
            return 0;
        }
        int[] dp = new int[nums.length];
        Arrays.fill(dp, Integer.MAX_VALUE);
        dp[0] = 0;
        for (int i = 1; i <= nums[0] && i < nums.length; i++) {
            dp[i] = 1;
        }
        for (int i = 1; i < nums.length; i++) {
            for (int j = 0; j <= nums[i]; j++) {
                if (i + j < nums.length && dp[i + j] == Integer.MAX_VALUE) {
                    dp[i + j] = dp[i] + 1;
                }
            }
            if (dp[nums.length - 1] != Integer.MAX_VALUE) {
                return dp[nums.length - 1];
            }
        }
        return dp[nums.length - 1];
    }
} 
                


















