题目描述

leetcode题目：1934. 确认率

Code

select 
    Signups.user_id,
    ifnull(confirmation_rate1, 0) as confirmation_rate
from Signups
left join(
    select 
        user_id,
        round(sum(if(action='confirmed', 1, 0))/count(*), 2) as confirmation_rate1
    from Confirmations
    group by user_id
) A on A.user_id = Signups.user_id

执行用时分布628ms，击败60.46%使用 MySQL 的用户