序言
最近监控扫描出我们项目的某些异常信息,报错java.lang.IllegalStateException: Duplicate key xxx,看到异常来自stream流,然后定位看了一下是某位同事的代码使用stream流把List转Map集合出现重复的key异常信息。List集合A对象来源于某个接口的返回,使用A对象的uuid成员变量作为key,理论上uuid作为唯一标识不应该有重复。
所以正确的做法是:
1)找该接口对应责任人,定位看List对象A的uuid为什么出现重复;
2)查看本项目代码中的异常来源;
java.util.stream.Collectors
Java 8版本引入Stream流式数据处理方式,使得可以对集合进行更简单高效的操作。
API文档链接如下:
- oracle.com/javase/8/doc/stream
- microsoft.com/api/java.util.stream.collectors
异常根因
首先看一段示例代码,
import lombok.AllArgsConstructor;
import lombok.Builder;
import lombok.Data;
import lombok.NoArgsConstructor;
import java.util.ArrayList;
import java.util.List;
import java.util.Map;
import java.util.stream.Collector;
import java.util.stream.Collectors;
public class DuplicateKeyDemo {
@AllArgsConstructor
@NoArgsConstructor
@Data
@Builder
private static class Employee {
private int identifierId;
private String name;
private int age;
}
public static void main(String[] args) {
List<Employee> employList = new ArrayList<>();
employList.add(new Employee(1, "Mike", 25));
employList.add(new Employee(2, "Mary", 26));
employList.add(new Employee(3, "Jack", 28));
employList.add(new Employee(4, "Tom", 23));
employList.add(new Employee(5, "Lucy", 21));
employList.add(new Employee(6, "Jim", 26));
employList.add(new Employee(7, "David", 29));
employList.add(new Employee(8, "Jack", 22));
employList.add(new Employee(8, "Jack", 25));
Collector<Employee, ?, Map<String, Integer>> collector = Collectors.toMap(Employee::getName, Employee::getAge);
Map<String, Integer> nameAgeIgnoreRepeatMap = employList.stream().collect(collector);
System.out.println(nameAgeIgnoreRepeatMap);
}
}
抛出的异常信息如下,
Exception in thread "main" java.lang.IllegalStateException: Duplicate key 28
at java.util.stream.Collectors.lambda$throwingMerger$0(Collectors.java:133)
at java.util.HashMap.merge(HashMap.java:1254)
at java.util.stream.Collectors.lambda$toMap$58(Collectors.java:1320)
at java.util.stream.ReduceOps$3ReducingSink.accept(ReduceOps.java:169)
at java.util.ArrayList$ArrayListSpliterator.forEachRemaining(ArrayList.java:1382)
at java.util.stream.AbstractPipeline.copyInto(AbstractPipeline.java:482)
at java.util.stream.AbstractPipeline.wrapAndCopyInto(AbstractPipeline.java:472)
at java.util.stream.ReduceOps$ReduceOp.evaluateSequential(ReduceOps.java:708)
at java.util.stream.AbstractPipeline.evaluate(AbstractPipeline.java:234)
at java.util.stream.ReferencePipeline.collect(ReferencePipeline.java:499)
at com.hust.zhang.stream.DuplicateKeyDemo.main(DuplicateKeyDemo.java:43)
直接点到HashMap的merge方法时,Map中已经存在28岁的Jack,新来的一条数据是22岁的Jack,那么在执行remappingFunction.apply(old.value, value)时就会报错java.lang.IllegalStateException: Duplicate key 28

解决方案
如果假设我们在这个Map里就是可以被覆盖,那么应该怎么做?
import lombok.AllArgsConstructor;
import lombok.Builder;
import lombok.Data;
import lombok.NoArgsConstructor;
import java.util.ArrayList;
import java.util.List;
import java.util.Map;
import java.util.stream.Collector;
import java.util.stream.Collectors;
public class DuplicateKeyDemo {
@AllArgsConstructor
@NoArgsConstructor
@Data
@Builder
private static class Employee {
private int identifierId;
private String name;
private int age;
}
public static void main(String[] args) {
List<Employee> employList = new ArrayList<>();
employList.add(new Employee(1, "Mike", 25));
employList.add(new Employee(2, "Mary", 26));
employList.add(new Employee(3, "Jack", 28));
employList.add(new Employee(4, "Tom", 23));
employList.add(new Employee(5, "Lucy", 21));
employList.add(new Employee(6, "Jim", 26));
employList.add(new Employee(7, "David", 29));
employList.add(new Employee(8, "Jack", 22));
employList.add(new Employee(8, "Jack", 25));
Collector<Employee, ?, Map<String, Integer>> antiCollisionCollector = Collectors.toMap(Employee::getName,
Employee::getAge, (oldValue, newValue) -> oldValue);
Map<String, Integer> nameAgeMap = employList.stream().collect(antiCollisionCollector);
System.out.println(nameAgeMap);
}
}
针对原来代码改了一行,在Collectors.toMap方法后面追加(oldValue, newValue) -> oldValue,表示当出现冲突时取初始出现值,如下图,执行remappingFunction.apply(old.value, value)方法时返回初始值28,

如果改成(oldValue, newValue) -> newValue则在本示例中返回重复对象的末尾值25。
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